LinkedIn Tango #630 Answer & Analysis

The given Suns in R2C2 and R2C3 cannot extend into a third Sun, so R2C1 and R2C4 must be Moons. That makes the Cross clues above them force Suns in R1C1 and R1C4, and the Equal clue between R1C2 and R1C3 forces both of those cells to be Moons.

Row 4 has two given Suns in the middle, so the next cell to the right must be a Moon to avoid three Suns in a row. That Moon then transfers upward through the Equal clue, and the remaining cells on that row must alternate in a way that keeps the row balanced. This also forces the first cell of that row to be a Sun.

With the first and third columns partly fixed, the remaining cells in those columns become forced by balance. That locks the left side of rows 5 and 6, and the fourth column then forces the middle of row 3. Once R3C4 is fixed as a Moon, the Cross clue makes R3C5 a Sun, and the Equal clue keeps R3C6 as a Moon.

Row 5 begins with two Moons once the left-side columns are balanced, so the next two cells have to be Suns to keep the row legal. But that means the fifth cell must stay a Moon, and the final cell in the row becomes a Sun to preserve the 3-and-3 split. Column 2 then forces the matching symbol in row 6.

The last unfinished spots are in columns 5 and 6. Column 5 already has enough symbols to force R6C5 as a Moon, and column 6 then forces R6C6 as a Sun. With those set, the top two cells in those columns also become fixed, completing the entire grid without breaking any row, column, Equal, or Cross clue.